1/(1-t)+6/(1+t)+36/(1-t^2)=0

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Solution for 1/(1-t)+6/(1+t)+36/(1-t^2)=0 equation:


D( t )

1-t = 0

1-t^2 = 0

t+1 = 0

1-t = 0

1-t = 0

1-t = 0 // - 1

-t = -1 // * -1

t = 1

1-t^2 = 0

1-t^2 = 0

-1*t^2 = -1 // : -1

t^2 = 1

t^2 = 1 // ^ 1/2

abs(t) = 1

t = 1 or t = -1

t+1 = 0

t+1 = 0

t+1 = 0 // - 1

t = -1

t in (-oo:-1) U (-1:1) U (1:+oo)

1/(1-t)+6/(t+1)+36/(1-t^2) = 0

(1*(t+1)*(1-t^2))/((1-t)*(t+1)*(1-t^2))+(6*(1-t)*(1-t^2))/((1-t)*(t+1)*(1-t^2))+(36*(1-t)*(t+1))/((1-t)*(t+1)*(1-t^2)) = 0

1*(t+1)*(1-t^2)+6*(1-t)*(1-t^2)+36*(1-t)*(t+1) = 0

5*t^3-7*t^2-36*t^2-5*t+7+36 = 0

5*t^3-43*t^2-5*t+43 = 0

5*t^3-43*t^2-5*t+43 = 0

5*t^3-43*t^2-5*t+43 = 0

{ 1, -1, 43, -43 }

1

t = 1

5*t^3-43*t^2-5*t+43 = 0

1

t-1

5*t^2-38*t-43

5*t^3-43*t^2-5*t+43

t-1

5*t^2-5*t^3

43-38*t^2-5*t

38*t^2-38*t

43-43*t

43*t-43

0

5*t^2-38*t-43 = 0

DELTA = (-38)^2-(-43*4*5)

DELTA = 2304

DELTA > 0

t = (2304^(1/2)+38)/(2*5) or t = (38-2304^(1/2))/(2*5)

t = 43/5 or t = -1

t in { -1, 43/5, 1}

(t+1)*(t-43/5)*(t-1) = 0

((t+1)*(t-43/5)*(t-1))/((1-t)*(t+1)*(1-t^2)) = 0

((t+1)*(t-43/5)*(t-1))/((1-t)*(t+1)*(1-t^2)) = 0 // * (1-t)*(t+1)*(1-t^2)

(t+1)*(t-43/5)*(t-1) = 0

( t+1 )

t+1 = 0 // - 1

t = -1

( t-1 )

t-1 = 0 // + 1

t = 1

( t-43/5 )

t-43/5 = 0 // + 43/5

t = 43/5

t in { -1}

t in { 1}

t = 43/5

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